Modified Euler’s Method

Write a program in C to solve 𝒇𝒓𝒂𝒄𝒅𝒚𝒅𝒙 = 𝒙 + 𝒚 with 𝒚(𝟎) = 𝟏 at 𝒙 = 𝟎. 𝟏 using the Modified Euler’s Method.

#include <stdio.h>
#include <conio.h>
double f(double x,double y){ return x + y; }
int main(){
    clrscr();
    double x=0,y=1,h=0.1,yn,yc;
    yn = y + h*f(x,y);
    yc = y + h*(f(x,y) + f(x+h,yn))/2;
    y = yc; x = x + h;
    printf("\n\n\ty(%.1f)=%.4f\n",x,y);
    getch();
    return 0;
}

Output